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Chapter 4 / Preferences and Utility Functions

4.4 Transforming Utility Functions


In the previous example we showed that doubling the utility generated by each bundle did not affect the location of indifference curve through a bundle, and did not change the MRS at any bundle.

Doubling is one example of a positive monotonic transformation of a function: that is, a transformation that raises or lowers the number of utils generated by a utility function, without changing the relative utility of any bundles. More formally, it is a continuously increasing function $f(u)$, so if $u_1 > u_2$ then $f(u_1) > f(u_2)$. Doubling the utility just means $f(u) = 2u$. If $u \ge 0$ for all potential bundles, we can also use exponential transformations like $f(u) = \ln u$, $f(u) = \sqrt{u}$, or $f(u) = u^2$.

Given such a function, we can show mathematically that the MRS is unaffected by a positive monotonic transformation. For example, take our utility function above, $u(x_1,x_2) = \sqrt{x_1x_2}$, which we can also write as $u(x_1,x_2) = x_1^{1 \over 2}x_2^{1 \over 2}$. The MRS of this utility function is \(MRS = {MU_1 \over MU_2} = \frac{\frac{1}{2}x_1^{-{1 \over 2}}x_2^{1 \over 2}}{\frac{1}{2}x_1^{1 \over 2}x_2^{-{1 \over 2}}} = {x_2 \over x_1}\) If we double the utility function, we get \(u(x_1,x_2) = 2x_1^{1 \over 2}x_2^{1 \over 2} \ \ \Rightarrow\ \ MRS = \frac{x_1^{-{1 \over 2}}x_2^{1 \over 2}}{x_1^{1 \over 2}x_2^{-{1 \over 2}}} = {x_2 \over x_1}\) If we take the natural log of the utility function, we get \(u(x_1,x_2) = \tfrac{1}{2}\ln x_1 + \tfrac{1}{2}\ln x_2 \ \ \Rightarrow\ \ MRS = \frac{\frac{1}{2x_1}}{\frac{1}{2x_2}} = {x_2 \over x_1}\) Finally, if we square the utility function, we get \(u(x_1,x_2) = x_1x_2 \ \ \Rightarrow\ \ MRS = {x_2 \over x_1}\) Therefore, the expression for the MRS is unaffected by a transformation.

Normalizing utility

It will often be useful to use positive monotonic transformations to “normalize” a utility function. For example, let’s take the utility function \(u(x_1,x_2) = ax_1 + bx_2\) where $a>0$ and $b>0$. This is a linear utility function (what we’ll introduce in a moment as “perfect substitutes”) in which each unit of good 1 yields $a$ utils and each unit of good 2 yields $b$ utils. If we multiply this by $1/(a+b)$, we get the transformed utility function \(\hat u(x_1,x_2) = \tfrac{a}{a+b}x_1 + \tfrac{b}{a+b}x_2\) Again, since we’re just multiplying the utility function by a constant, this doesn’t affect the MRS: you can check to see that it’s still $a/b$.

By construction, the coefficients on $x_1$ and $x_2$ now sum to 1: \({a \over a+b} + {b \over a+b} = {a + b \over a+b} = 1\) Let’s write \(\alpha = {a \over a+b}\) Therefore \({b \over a + b} = 1 - {a \over a + b} = 1 - \alpha\) So our new utility function becomes \(\hat u(x_1,x_2) = \alpha x_1 + (1-\alpha) x_2\) In this formulation, we can interpret $\alpha$ as being the relative weight this utility function places on good 1, with $1 - \alpha$ being the relative weight it places on good 2. This allows us to express an agent’s preferences in terms of the single variable $\alpha$ rather than two variables $a$ and $b$.

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